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An electron of mass m, moves around the ...

An electron of mass m, moves around the nucleus in a circular orbit of radius .r. under the action of centripetal force .F.. The equivalent electric current is

A

`(e)/(2pi)sqrt((F)/(mr))`

B

`2pi esqrt((F)/(mr))`

C

`(e)/(pi)sqrt((F)/(mr))`

D

`(e)/(2pi)sqrt((mr)/(F))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equivalent electric current \( I \) for an electron moving in a circular orbit around a nucleus, we can follow these steps: ### Step 1: Understand the Concept of Electric Current Electric current \( I \) is defined as the flow of charge per unit time. Mathematically, it can be expressed as: \[ I = \frac{Q}{t} \] where \( Q \) is the charge and \( t \) is the time. ### Step 2: Determine the Charge and Time Period For an electron, the charge \( Q \) is equal to the elementary charge \( e \). The time period \( T \) for one complete revolution in a circular orbit of radius \( r \) can be expressed in terms of the velocity \( v \): \[ T = \frac{2\pi r}{v} \] Thus, the current can be rewritten as: \[ I = \frac{Q}{T} = \frac{e}{T} = \frac{e \cdot v}{2\pi r} \] ### Step 3: Relate Velocity to Centripetal Force The centripetal force \( F \) acting on the electron is given by: \[ F = \frac{mv^2}{r} \] From this, we can express the velocity \( v \) in terms of \( F \): \[ v^2 = \frac{Fr}{m} \quad \Rightarrow \quad v = \sqrt{\frac{Fr}{m}} \] ### Step 4: Substitute Velocity into the Current Equation Substituting the expression for \( v \) into the current equation: \[ I = \frac{e \cdot \sqrt{\frac{Fr}{m}}}{2\pi r} \] ### Step 5: Simplify the Expression Now, simplifying the expression for \( I \): \[ I = \frac{e}{2\pi r} \cdot \sqrt{\frac{Fr}{m}} = \frac{e}{2\pi} \cdot \sqrt{\frac{F}{m}} \cdot \frac{1}{\sqrt{r}} \] ### Final Expression Thus, the equivalent electric current \( I \) is given by: \[ I = \frac{e}{2\pi} \sqrt{\frac{F}{m}} \cdot \frac{1}{\sqrt{r}} \]
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