Home
Class 12
PHYSICS
In the circuit shown in figure Cur...

In the circuit shown in figure

Current through `R_(2)` is zero if `R_(4) = 2 Omega` and `R_(3) = 4 Omega` In this case

A

current through `R_(3)` is 2A

B

current through `R_(4)` is 3A

C

both (a) and (b) are correct

D

both (a) and (b) wrong

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-IV LEVEL- II (ADVANCED) (Integer Type Questions))|4 Videos

  • CURRENT ELECTRICITY

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-V LEVEL - I (MAIN) (Straight Objective Type Questions))|6 Videos

  • CURRENT ELECTRICITY

    AAKASH SERIES|Exercise LECTURE SHEET (EXERCISE-IV LEVEL- II (ADVANCED) (Straight Objective Type Questions))|2 Videos

  • CURRENT ELECTRICITY

    AAKASH SERIES|Exercise PROBLEMS (LEVEL-II)|27 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    AAKASH SERIES|Exercise PRACTICE EXERCISEX|42 Videos

Similar Questions

Explore conceptually related problems

Consider the circuit shown in fig. Current through R_2 is zero if R_4 = 2Omega and R_3 = 4 Omega in this case

Passage : In the circuit shown in figure : Current through R_(1) is independent of :

Knowledge Check

  • For the circuit shown in the figure, the current in the 4 Omega resistor is

    A
    `0.5A`
    B
    `0.25 A`
    C
    1A
    D
    `1.5 A`

    • Similar Questions

    Explore conceptually related problems

    Find the current flowing through the resistance R_(1) of the circuit shown in Fig. If the resistances are equal to R_(1) = 10 Omega. R_(2) = 20 Omega and R_(3) = 30 Omega , and the potential of points 1,2 and 3 are equal to varphi_(1) = 10 V, varphi_(2) = 6V , and varphi_(3) = 5 V

    In the figure shown the current flowing through 2R is:

    In the circuit shown in figure For what ratio (R_(2))/(R_(4)) , current through R_(3) will be zero

    In the circuit shown below E_(1) = 4.0 V, R_(1) = 2 Omega, E_(2) = 6.0 V, R_(2) = 4 Omega and R_(3) = 2 Omega . The current I_(1) is

    In the curcuit shown in figure R_1=R_2=R_3=10Omega . Find the currents through R_1 and R_2

    (a) Find the equivalent resistance between A and B of the network extending off to the infinity shown in the figure . (b) If E = 12 V , R_(1) = 1 Omega and R_(2) = 4 Omega . Find the current in R_(2) nearest of the battery .

    In the circuit shows in Fig E = 15 V , R_(1) = 1Omega , R_(2) = 1 Omega , R_(3) = 2Omega , and L = 1.5 H . The currents flowing through R_(1),R_(2) ,and R_(3) are i_(1),i_(2) , and i_(3) , respectively. Immediately after tuning switch S on,

    Home
    Profile