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Consider the situation shown in figure.T...

Consider the situation shown in figure.The switch is closed at `t=0`when the capacitors are uncharged. find the charge on the capacitor `C_(1)`as a function of time `t`.

A

`q=epsilonC(1-e^(-(t)/(rC)))` where `C=(C_(1)C_(2))/(C_(1)+C_(2))`

B

`q=(epsilonC)/(2)(1-e^(-(t)/(rC)))` where `C=C_(1)+C_(2)`

C

`q=epsilonC(1-e^(-(t)/(rC)))` where `C=C_(1)+C_(2)`

D

`q=epsilonCe^(-(t)/(nC))` where `C=(C_(1)C_(2))/(C_(1)+C_(2))`

Text Solution

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The correct Answer is:
A
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