What is the self inductance of an air core solenoid 50cm long and 2cm radius if it has 500 turns? Find the magnetic flux when a current of 2 amp passes through it

Explanation

To solve the problem step by step, we will first calculate the self-inductance of the air core solenoid and then find the magnetic flux when a current of 2 A passes through it.

### Step 1: Identify the given values
- Length of the solenoid, \( l = 50 \, \text{cm} = 50 \times 10^{-2} \, \text{m} = 0.5 \, \text{m} \)
- Radius of the solenoid, \( r = 2 \, \text{cm} = 2 \times 10^{-2} \, \text{m} = 0.02 \, \text{m} \)
- Number of turns, \( N = 500 \)
- Current, \( I = 2 \, \text{A} \)

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