Home
Class 12
PHYSICS
For the circuit shown in Fig. find 1) ...

For the circuit shown in Fig. find
1) the output voltage
2) the voltage drop across series resistance,
3) the current through Zener diode.

Text Solution

Verified by Experts

1) 50V,2)70V ,3) 9mA
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise Problems (LEVEL-II)|9 Videos
  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise EXAMPLES|56 Videos
  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise Exercise (very Short answer questions)|36 Videos
  • RAY OPTICS

    AAKASH SERIES|Exercise PROBLEMS ( LEVEL-II)|60 Videos
  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos

Similar Questions

Explore conceptually related problems

In the given circuit, the current through zener diode is :

In the circuit, Fig The current through the zener diode is

For the circuit shown below, the current through the Zener diode is

In the given circuit the current through Zener Diode is close to :

In the circuit shown in Fig. 5.79, determine the voltage drop between A and D.

From the Zener diode circuit shown in figure, the current through the Zener diode is

For the circuit shown in figure, find the voltage acrss 10Omega resistor and the current passing through it.

In the following circuit the current flowing through zener diode is

In the circuit shown in figure, if the diode forward voltage drop is 0.3 V, then the voltage difference between A to B is,

In the circuit shown in figure, if the A diode forward voltage drop is 0.3 V, the voltage difference between A and B is

AAKASH SERIES-SEMICONDUCTOR DEVICES-Problems (LEVEL-I)
  1. Find maximum voltage across AB in the circuit shown in figure. Assume ...

    Text Solution

    |

  2. The diode used in the circuit shown in the figure has a constant volta...

    Text Solution

    |

  3. For the circuit shown in Fig. find 1) the output voltage 2) the vo...

    Text Solution

    |

  4. The applied input AC power to a half wave rectifier is 190W. The DC ou...

    Text Solution

    |

  5. A p-n diode is used in a half wave rectifier with a load resistance of...

    Text Solution

    |

  6. A full wave rectifier uses two diodes with a load resistance of 100 O...

    Text Solution

    |

  7. A full-wave rectifier is used to convert 50 Hz A.C into D.C, then the ...

    Text Solution

    |

  8. In an N-P-N transistor operating in the active region, the collector c...

    Text Solution

    |

  9. In a common base configuration, with a base current of 0.005 mA, the e...

    Text Solution

    |

  10. For a transistor 'alpha' = 0.98 and emitter current I(E) = 2.5 mA. Cal...

    Text Solution

    |

  11. In common base configuration of a transistor, a change of 200 mV in em...

    Text Solution

    |

  12. In a transistor the emitter current is 1.01 times as large as the coll...

    Text Solution

    |

  13. In a transistor circuit the base current changes from 30 muA to 90muA....

    Text Solution

    |

  14. The constant a of a transistor is 0.9. What would be the change in col...

    Text Solution

    |

  15. For a transistor, the current gain of common-base configuration is 0.8...

    Text Solution

    |

  16. The current gain of a transistor in common emitter circuit is 49. Calc...

    Text Solution

    |

  17. A change of 0.5 mA in the emitter current of a transistor produces a c...

    Text Solution

    |

  18. A change of 200mV in base-emitter voltage causes a change of 100μA in ...

    Text Solution

    |

  19. For a single transistor amplifier, the collector load is R(L) =22kOmeg...

    Text Solution

    |

  20. AP-N-P transistor is used in common-emitter mode in an amplifier circu...

    Text Solution

    |