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The applied input AC power to a half wav...

The applied input AC power to a half wave rectifier is 190W. The DC output power obtained is 40 W. Find the rectifier efficiency.

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To find the rectifier efficiency of a half wave rectifier given the input AC power and the output DC power, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Values**: - Input AC power (P_ac) = 190 W - Output DC power (P_dc) = 40 W ...
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AAKASH SERIES-SEMICONDUCTOR DEVICES-Problems (LEVEL-I)
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  2. For the circuit shown in Fig. find 1) the output voltage 2) the vo...

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  3. The applied input AC power to a half wave rectifier is 190W. The DC ou...

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  4. A p-n diode is used in a half wave rectifier with a load resistance of...

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  5. A full wave rectifier uses two diodes with a load resistance of 100 O...

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  12. In a transistor circuit the base current changes from 30 muA to 90muA....

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  14. For a transistor, the current gain of common-base configuration is 0.8...

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  16. A change of 0.5 mA in the emitter current of a transistor produces a c...

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  17. A change of 200mV in base-emitter voltage causes a change of 100μA in ...

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  18. For a single transistor amplifier, the collector load is R(L) =22kOmeg...

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