Home
Class 12
PHYSICS
A full-wave rectifier is used to convert...

A full-wave rectifier is used to convert 50 Hz A.C into D.C, then the number of pulses per second present in the rectified voltage is

Text Solution

Verified by Experts

120
Promotional Banner

Topper's Solved these Questions

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise Problems (LEVEL-II)|9 Videos

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise EXAMPLES|56 Videos

  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise Exercise (very Short answer questions)|36 Videos

  • RAY OPTICS

    AAKASH SERIES|Exercise PROBLEMS ( LEVEL-II)|60 Videos

  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos

Similar Questions

Explore conceptually related problems

A diode, a resistor and a 50 Hz AC source are connected in series. The number of current pulses per second through the resistor is

If a full wave rectifier circuit is operating from 50 Hz mains, the fundamental frequency in the ripple frequency will be

In a full wave rectifier circuit operating from 50 Hz mains frequency , the fundamental frequency in the ripple would be

Using an ac voltmeter, the potential difference in the electrical line in a house is read to be 234 V. If the line freqency is known to be 50 cycles per second, the equation for the line voltage is

In a half wave rectifier circuit operating from 50 Hz mains frequency, the fundamental frequency in the ripple would be

A source of sound of frequency 1000 Hz moves to the right with a speed of 32(m)/(s) relative to the ground. To its right there is a reflecting surface moving to the left with a speed of 64(m)/(s) relative to the ground. Take the speed of 64(m)/(s) . Relative to the ground. Take the speed of sound in air to be 332(m)/(s) and find (a) The wavelength of the sound emitted in air by the source, (b) the number of waves per second arriving at the reflecting surface, (c ) The speed of the reflected waves and (d) The wavelength of the reflected waves.

A full wave rectifier circuit along with the input and output are shown in the figure. The contribution from the diode D_(2) is (are)

A fullwave P.N diode rectifier used load resistor of 1500 Omega . No filter is used. Assume each diode to have idealized characteristic with R_(f) = 10 Omega and R_(r) = ac . Since wave voltage applied to each diode has amplitude of 30 volts and frequency 50 Hz. Calculate. (i) Peak, d.c rms load current (ii) d.c power output (iii) A.C power input (iv) Rectifier efficiency.

A tuning fork A, marked 512 Hz, produces 5 beats per second, when sounded with another unmarked tuning fork B. If B is loaded with wax, the number of beats is again 5 per second. What is the frequency of tuning fork B when not loaded? a) 502 Hz b) 507 Hz c) 517 Hz d) 522 Hz

A column of air at 51^(@) C and a tuning fork produce 4 beats per second when sounded together. As the temperature of the air column is decreased, the number of beats per second tends to decrease and when the temperature is 16^(@) C the two produce 1 beat per second. Find the frequency of the tuning fork.

AAKASH SERIES-SEMICONDUCTOR DEVICES-Problems (LEVEL-I)
  1. For the circuit shown in Fig. find 1) the output voltage 2) the vo...

    Text Solution

    |

  2. The applied input AC power to a half wave rectifier is 190W. The DC ou...

    Text Solution

    |

  3. A p-n diode is used in a half wave rectifier with a load resistance of...

    Text Solution

    |

  4. A full wave rectifier uses two diodes with a load resistance of 100 O...

    Text Solution

    |

  5. A full-wave rectifier is used to convert 50 Hz A.C into D.C, then the ...

    Text Solution

    |

  6. In an N-P-N transistor operating in the active region, the collector c...

    Text Solution

    |

  7. In a common base configuration, with a base current of 0.005 mA, the e...

    Text Solution

    |

  8. For a transistor 'alpha' = 0.98 and emitter current I(E) = 2.5 mA. Cal...

    Text Solution

    |

  9. In common base configuration of a transistor, a change of 200 mV in em...

    Text Solution

    |

  10. In a transistor the emitter current is 1.01 times as large as the coll...

    Text Solution

    |

  11. In a transistor circuit the base current changes from 30 muA to 90muA....

    Text Solution

    |

  12. The constant a of a transistor is 0.9. What would be the change in col...

    Text Solution

    |

  13. For a transistor, the current gain of common-base configuration is 0.8...

    Text Solution

    |

  14. The current gain of a transistor in common emitter circuit is 49. Calc...

    Text Solution

    |

  15. A change of 0.5 mA in the emitter current of a transistor produces a c...

    Text Solution

    |

  16. A change of 200mV in base-emitter voltage causes a change of 100μA in ...

    Text Solution

    |

  17. For a single transistor amplifier, the collector load is R(L) =22kOmeg...

    Text Solution

    |

  18. AP-N-P transistor is used in common-emitter mode in an amplifier circu...

    Text Solution

    |

  19. The input resistance of a common-emitter amplifier is 600 Omega and lo...

    Text Solution

    |

  20. If voltage gain in CE configuration is 24. If R(e)=10 k, R(c) = 10. B ...

    Text Solution

    |