A semiconductor has an electron concentration of `0.45 xx 10^(12) m^(-3)` and a hole concentration of `5.0 xx 10^(20) m^(-3)` Calculate its conductivity. Given electron mobility `=0.135 m^2 V^(-1) s^(-1)` , hole mobility` =0.048m^2 V^(-1) s^(-1) `

Explanation

To calculate the conductivity of the given semiconductor, we will follow these steps:

### Step 1: Understand the Formula for Conductivity
The total conductivity (\( \sigma \)) of a semiconductor can be expressed as the sum of the conductivities due to electrons and holes:
\[ \sigma = \sigma_e + \sigma_h \]
Where:
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