The circuit shown in figure contains two diodes each with a forward resistance of `50Ω` and infinite reverse resistance.If the battery voltage is 6 v ,then the current through the `100Ω` resistance is

Explanation

As per given circuit, diode `D_1 ` is forward biased and offers a resistance of 50 ohm. Diode `D_2` is reverse biased and as its corresponding resistance circuit is as shown in Fig. As all the three resistances are in series, the current through them is

` I=(6V )/( (50+150 + 100 ) W ) =(6)/(300 )A = 0.02A`