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A p-n diode is used in a half wave recti...

A p-n diode is used in a half wave rectifier with a load resistance of `1000 Omega `. If the forward resistance (`r_f`) of diode is `10 Omega `, calculate the efficiency of this half wave rectifier.

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To calculate the efficiency of a half-wave rectifier using a p-n diode, we can follow these steps: ### Step 1: Understand the Given Values We have the following values provided: - Load resistance, \( R_L = 1000 \, \Omega \) - Forward resistance of the diode, \( R_f = 10 \, \Omega \) ### Step 2: Write the Efficiency Formula ...
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AAKASH SERIES-SEMICONDUCTOR DEVICES-EXAMPLES
  1. The circuit shown in figure contains two diodes each with a forward re...

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  2. The applied input ac power to a half wave rectifier is 100 W. The dc o...

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  3. A p-n diode is used in a half wave rectifier with a load resistance of...

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  4. A full wave rectifier uses two diodes with a load resistance of 100 O...

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  5. The current through a P-N junction diode is 55mA at a forward bias vol...

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  6. Considering the circuit and data given in the diagram calculate the cu...

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  8. For the circuit shown in Fig. find the output voltage,

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  16. In a single state transistor amplifier,When the signal changes by 0.02...

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  19. In a transitor (Beta = 50), the voltage across 5 kOmega load resistanc...

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