Considering the circuit and data given in the diagram calculate the currents flowing in the diodes `D_(1)` and `D_(2)` with linear characteristics.Forward resistance of `D_(1)` and `D_(2)` is 20 `Omega`

Explanation

Since the positive terminal of battery is connected to P-type of both diodes `D_1` and `D_2`, they are forward biased. These diodes are replaced by with their forward resistances as shown in Fig.

The resistance of `20 Omega ` and `20 Omega ` in parallel
`(1)/(R ) =(1)/(20 ) +(1)/(20 ) =(2)/(20) (or) R=(20)/(2) = 10 Omega `
Therefore, total current I in the circuit
`I= (1)/(100+10 )= (1)/( 110 ) `amp and
` I_1 = I_2 = 1/2 xx (1)/(110) = (1) /(220 ) `amp