A full-wave rectifier is used to convert 'n'Hz a.c into d.c, then the number of pulses per second present in the rectified voltage is

Options

A. n
B. n/2
C. 2n
D. 4n

Answer

To solve the problem of determining the number of pulses per second present in the rectified voltage when using a full-wave rectifier to convert 'n' Hz AC into DC, we can follow these steps:

### Step-by-Step Solution

1. **Understand the Input Frequency**: The input frequency of the AC signal is given as 'n' Hz. This means that the AC waveform completes 'n' cycles in one second.

2. **Identify the Function of a Full-Wave Rectifier**: A full-wave rectifier converts both the positive and negative halves of the AC waveform into a pulsating DC signal. This means that for each cycle of the AC waveform, there will be two pulses in the output.

3. **Calculate the Pulses per Cycle**: Since a full-wave rectifier produces one pulse for the positive half-cycle and one pulse for the negative half-cycle, it effectively doubles the number of pulses generated from the input frequency. Therefore, for each cycle (which occurs 'n' times per second), there are 2 pulses.

4. **Determine Total Pulses per Second**: Since the input frequency is 'n' Hz and the full-wave rectifier produces 2 pulses for each cycle, the total number of pulses per second in the rectified output will be:
\[ \text{Total Pulses} = 2 \times n = 2n \]

5. **Conclusion**: The number of pulses per second present in the rectified voltage is \(2n\).

### Final Answer
The number of pulses per second present in the rectified voltage is \(2n\).

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