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Two wires AO and OC carry equal currents...

Two wires AO and OC carry equal currents i as shown in the figure where `angle AOC = theta` ,Find the magnitude of the magnetic field at the point P on the bisector of anlge `theta` at a distance 'r' from O. Assume that the other ends of both wires extend to infinity

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The direction of magnetic field due to both the wires AO and OC are out of page of paper
Due to wire OC
`B = (mu_0i)/(4pid){sin phi_1 + sin phi_2}`
`B = (mu_0i)/(4pisin""theta/2){sin (90 -theta/2) + sin 90}`
`B = (mu_0i)/(4pi sin ""theta/2)(1 + cos"" (theta)/(2))`
Due to both the wires, the net magnetic field is
`B = (2 xx mu_0i)/(4pir sin""theta/2)(1 + cos""theta/2)`
`B = (2 xx mu_0i)/(2pir sin""theta/2)(1 + cos""theta/2)`
`B = (mu_0)/(2pi) (i)/(r) cot ""(theta)/(4)`
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