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Two conductors each of length 12 m lie p...

Two conductors each of length 12 m lie parallel to each other in air. The centre to center distance between two conductors is `15 xx 10^(-2)` m and the current in each conductor is 300 amperes. Determine the force in newton tending to pull the conductors together.

Text Solution

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Force between two conductors is given by
`F = (mu_0)/(2pi) (i_1 i_2l)/(r)`
Given l = 12 m , `r = 15 xx 10^(-2) m`.
`i_1 = i_2 = 300 A`
`therefore F = 2 xx 10^(-7) xx (300 xx 300 xx 12)/(15 xx 10^(-2)) = 1.44 N`.
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