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The area of the coil in a moving coil ga...

The area of the coil in a moving coil galvanometer is 16 `cm^(2)` and has 20 turns. The magnetic induction is 0.2T and the couple per unit twist of the suspended wire is `10^(-6)` Nm per degree. If the deflection is 45° calculate the current passing through it.

Text Solution

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Given, `A = 16 cm^2 = 16 xx 10^(-4)m^2`
`B = 0.2 T, N = 20, C = 10^(-6) N`m/degree ` theta = 45^@`
From `C theta = BiAN`
`= i (C theta)/(BAN) = (10^(-6) xx 45)/(0.2 xx 16 xx 10^(-4) xx 20) = 7 xx 10^(-3) A.`
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