Home
Class 12
PHYSICS
A coil area 100 cm^(2) having 500 tums c...

A coil area 100 `cm^(2)` having 500 tums carries a current of 1 mA . It is suspended in a uniform magnetic field of induction `10^(-3) Wb//m^(2)`. Its plane makes an angle of 60° with the lines of induction. Find the torque acting on the coil.

Text Solution

Verified by Experts

Given i = 1 `mA = 10^(-3)` A , N= 500 `B = 10^(-3) Wb//m^2`
`theta = 60^@ , tau = ? A = 100 cm^2 = 100 xx 10^(-4) m^2`
Couple acting on the coil is given by `tau = BiA N sin phi` where `phi` is angle made by normal to the plane of coil with B.
`phi = 90 - 60 = 30^@`
`therefore C = 10^(-3) xx 10^(-3) xx 100 xx 10^(-4) xx 500 xx sin 30^@`
`= 250 xx 10^(-8)` Nm
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETICS

    AAKASH SERIES|Exercise EXERCISE (LONG ANSWER QUESTIONS)|5 Videos
  • ELECTROMAGNETICS

    AAKASH SERIES|Exercise EXERCISE (SHORT ANSWER QUESTIONS)|6 Videos
  • ELECTROMAGNETIC WAVES

    AAKASH SERIES|Exercise EXERCISE -II|22 Videos
  • ELECTROSTATICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED) INTEGER TYPE QUESTIONS)|5 Videos

Similar Questions

Explore conceptually related problems

A rectangul ar coil of wire of 100 turns and 10 xx 15cm^(2) size carrying a current of 2Amp. is in a magnetic field of induction 2 xx 10^(-3)wb//m^(2) . If the normal drawn to the plane of the coil makes an angle 30° with the field, then the torque on the coil is

A circular coil of 100turns radius 10cm, carries a current of 5A. It is suspended vertically in a uniform horizontal magnetic field of 0.5T and the field lines make an angle of 60^(@) with the plane of the coil. The magnitude of the torque that must be applied on it to prevent it from turning is

A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is

A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30^(@) with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning is

A rectangular loop of area 5m^(2) , has 50 turns and carries a current of 1A. It is held in a uniform magnetic field of 0.1T, at an angle of 30^(@) . Calculate the torque experienced by the coil.

A rectangular coil 20cmxx20cm has 100 turns and carries a current of 1 A . It is placed in a uniform magnetic field B=0.5 T with the direction of magnetic field parallel to the plane of the coil. The magnitude of the torque required to hold this coil in this position is

A rectangular coil 20cmxx20cm has 100 turns and carries a current of 1 A . It is placed in a uniform magnetic field B=0.5 T with the direction of magnetic field parallel to the plane of the coil. The magnitude of the torque required to hold this coil in this position is

A circular disc of radius 0.2 m is placed in a uniform magnetic fied of induction (1)/(pi) ((Wb)/(m^(2))) in such a way that its axis makes an angle of 60^(@) with B . The magnetic flux linked with the disc is

A coil of area 5cm^(2) and having 20 turns is placed in a uniform magnetic field of 10^(3) gauss. The normal to the plane of the coil makes an angle of 60^(@) with the magnetic field. The flux in Maxwell through the coil is:

A coil of area 5cm^(2) and having 20 turns is placed in a uniform magnetic field of 10^(3) gauss. The normal to the plane of the coil makes an angle of 60^(@) with the magnetic field. The flux in Maxwell through the coil is: