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A galvanometer of resistance 20Omega is ...

A galvanometer of resistance `20Omega` is shunted by a `2Omega` resistor. What part of the main current flows through the galvanometer ?

Text Solution

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`i_g/i = (S)/(G +S)`. Given `G = 20 Omega , S = 2 Omega`
`therefore i_g/i = 2/22 = 1/11 , 1/11` th part of current passes through galvanometer.
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