Home
Class 12
PHYSICS
A maximum current of 0.5 mA can be passe...

A maximum current of 0.5 mA can be passed through a galvanometer of resistance `20Omega`. Calculate the resistance to be connected in series to convert it into a voltmeter of range `(0- 5)V`.

Text Solution

Verified by Experts

`R = G(n-1) , " where " n = (V_2)/(V_1)`
`V_2 = 5 V , V_1 = i G = 0.5 xx 10^(-3) xx 20 = 10^(-2) V`
`therefore n = 500`
and R = 20 (500 -1)
`= 9980 Omega`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETICS

    AAKASH SERIES|Exercise EXERCISE (LONG ANSWER QUESTIONS)|5 Videos

  • ELECTROMAGNETICS

    AAKASH SERIES|Exercise EXERCISE (SHORT ANSWER QUESTIONS)|6 Videos

  • ELECTROMAGNETIC WAVES

    AAKASH SERIES|Exercise EXERCISE -II|22 Videos

  • ELECTROSTATICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (PRACTICE SHEET (ADVANCED) INTEGER TYPE QUESTIONS)|5 Videos

Similar Questions

Explore conceptually related problems

The range of voltmeter of resistance 300 Omega is 5 V. The resistance to be connected to convert it into an ammeter of range 5 A is

In full scale deflection current in galvanometer of 100 ohm resistance is 1 mA. Resistance required in series to convert it into voltmeter of range 10 V.

A voltmeter has a resistance G and range V . Calculate the resistance to be used in series with it to extend its range to nV .

A voltmeter has a resistance G and range V . Calculate the resistance to be used in series with it to extend its range to nV .

100mA current gives a full scale deflection in a galvanometer of 2Omega resistance. The resistance connected with the galvanometer to convert it into a voltmeter to measure 5V is

When a current of 5mA is passed through a galvanometer having a coil of resistance 15Omega , it shows full sacle deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0-10V is:

The resistance of a galvanometer is 50 ohm and the maximum current which can be passed through it is 0.002 A. what resistance must be connected to it in order to convert it into an ammeter of range 0-0.5 A ?

In a ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G , the resistance of ammeter will be

If a galvanometer has full scale deflection current I_(g) and resistance G. A shunt resistance R_(A) is used to convert it into an ammeter of range I_(o) and a resistance R_(V) is connected in series to convert it into a voltmeter of range V_(0) such that V_(0)=I_(0)G then R_(A)R_(V) and (R_(A))/(R_(V)) respectively are:

The full scale deflection current of a galvanometer of resistance 1Omega is 5 mA . How will you convert it into a voltmeter of range of 5V ?