The area of the coil in a moving coil galvanometer is `8 cm^2` and has 10 turns. The magnetic induction is 0.1 T and the couple per unit twist of the suspended fibre is `10^(-6)` Nm per degree. If the deflection is `90^0`, calculate the current passing through it

Explanation

To solve the problem, we need to calculate the current passing through a moving coil galvanometer given the following parameters:

- Area of the coil, \( A = 8 \, \text{cm}^2 = 8 \times 10^{-4} \, \text{m}^2 \)
- Number of turns, \( N = 10 \)
- Magnetic induction, \( B = 0.1 \, \text{T} \)
- Couple per unit twist, \( C = 10^{-6} \, \text{Nm/degree} \)
- Deflection, \( \theta = 90^\circ \)

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