A galvanometer of resistance `30 Omega` is shunted by a `30 Omega` resistor. What part of the main current flows through the meter ?

Explanation

To solve the problem, we need to determine what part of the main current flows through the galvanometer when it is shunted by a resistor of equal resistance. Let's break it down step by step.

### Step-by-Step Solution:

1. **Identify Given Values**:
- Resistance of the galvanometer, \( R_g = 30 \, \Omega \)
- Resistance of the shunt resistor, \( R_s = 30 \, \Omega \)

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