A galvanometer has a resistance of `100 Omega`. A current of `2 xx 10^(-3)` A can pass through the galvanometer. How can it be converted into (a) Ammeter of range 20 A and (b) voltmeter of range 20 V?

Explanation

To convert a galvanometer into an ammeter and a voltmeter, we will follow the steps outlined below.

### Given:
- Resistance of the galvanometer (G) = 100 Ω
- Maximum current through the galvanometer (Ig) = 2 × 10^(-3) A
- Desired range for ammeter (I) = 20 A
- Desired range for voltmeter (V) = 20 V

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