A galvanometer has a resistance of `96 Omega`. If 4% of the main current is to be passed through the meter, what should be the value of the shunt?

Explanation

To solve the problem of finding the value of the shunt resistance needed for a galvanometer, we can follow these steps:

### Step 1: Understand the relationship between the galvanometer current and the main current
We know that 4% of the main current (I) is to be passed through the galvanometer (IG). This can be expressed mathematically as:
\[ \frac{I_G}{I} = \frac{4}{100} = \frac{1}{25} \]
From this, we can deduce:
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