A coil of 20 turns of area `8 xx 10^(-2) cm^2` with its plane parallel to the magnetic field of intensity 3000G and carrying a certain current experiences a torque `2.4 xx 10^(-3)` Nm .Calculate the value of current.

Explanation

To solve the problem, we need to calculate the current flowing through a coil given the torque experienced by the coil, the number of turns, the area of the coil, and the magnetic field intensity.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Number of turns, \( n = 20 \)
- Area of the coil, \( A = 8 \times 10^{-2} \, \text{cm}^2 \)
- Torque, \( \tau = 2.4 \times 10^{-3} \, \text{Nm} \)
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