The coil of a pivoted coil galvanometer has 25 turns and has area 10 cm 2. The coil is placed in a radial magnetic field of flux density `8 xx 10^(-2)` T. The torsional constant of the spring is ` 1.0 xx 10^(-6)` Nm per degree. Find the deflection of the coil for a current of 4m A.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the given values
- Number of turns (n) = 25
- Area of the coil (A) = 10 cm² = \(10 \times 10^{-4}\) m² = \(10^{-3}\) m²
- Magnetic flux density (B) = \(8 \times 10^{-2}\) T
- Torsional constant (c) = \(1.0 \times 10^{-6}\) Nm/degree
- Current (I) = 4 mA = \(4 \times 10^{-3}\) A
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