A galvanometer of resistance `40 Omega` can measure a current of 2mA for full scale deflection. It is converted into an ammeter having range 6 times the previous value by using proper shunt. Find the resistance of ammeter so formed ?

Explanation

To solve the problem, we need to find the resistance of the ammeter formed by converting the galvanometer with a shunt resistor. Here's the step-by-step solution:

### Step 1: Identify Given Values
- Resistance of the galvanometer, \( R_G = 40 \, \Omega \)
- Full-scale deflection current of the galvanometer, \( I_G = 2 \, \text{mA} = 0.002 \, \text{A} \)
- The new range of the ammeter is 6 times the previous value, so:
\[
I_{max} = 6 \times I_G = 6 \times 0.002 \, \text{A} = 0.012 \, \text{A} = 12 \, \text{mA}
...