Calculate the ratio of electric and gravitational force between two protons. Charge of each proton is `1.6 xx 10^(-19)C`, mass is `1.672 xx 10^(-27)kg and G= 6.67 xx 10^(-11) Nm^(2) kg^(-2)`.

Explanation

Electrostatic force between two protons is
`F_(1) =9xx10^(9) (Q_(1)Q_(2))/(r^(2))`
`Q_(1)=1.6xx10^(-19) C, Q_(2) =1.6xx10^(-19)C`
r is the distance between the two protons
Gravitational force between them : `F_(2)=(Gm_(1)m_(2))/(r^(2))`
`m_(1)=m_(2)=1.672 xx 10^(-27)kg `
`G=6.67xx10^(-11)Nm^(2)//kg^(2)`
`therefore (F_(1))/(F_(2)) =(9xx10^(9)Q_(1)Q_(2))/(G.m_(1)m_(2))`
`=(9xx10^(9) xx 1.6xx10^(-19)xx 1.6xx10^(-19))/(6.67xx10^(-11) xx 1.672 xx 10^(-27) xx 1.672 xx 10^(-27))`
`=1.23xx10^(36)`