A conducting bubble of radius a, thickness t (t << a) has potential V. Now, the bubble collapses into a droplet. The potential of the droplet will be:

Explanation

Here charge and mass are conserved. If R is the radius of the resulting drop formed and `rho` is density of soap solution,
`(4)/(3) piR^(3)rho=4pir^(2)t rho rArrR=(3r^(2)t)^(1//3)`
Now potential of the bubble is `V=(1)/(4pi in_(0))(q)/(r )`
or `q=4pi in_(0)rV`
Now potential of resulting drop is
`V^(1)=(1)/(4pi in_(0)) (q)/(R ) =((r )/(3t))^(1//3)V`.