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15.0 g of an unknown molecular material ...

`15.0 g` of an unknown molecular material was dissolved in `450 g` of water. The reusulting solution was found to freeze at `-0.34 .^(@)C`. What is the the molar mass of this material. (`K_(f)` for water `= 1.86 K kg mol^(-1)`)

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To find the molar mass of the unknown molecular material, we can follow these steps: ### Step 1: Understand the Freezing Point Depression Formula The freezing point depression (\( \Delta T_f \)) can be calculated using the formula: \[ \Delta T_f = K_f \times m \] where: ...
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(a) Define the following terms : (i) Mole fraction (ii) Ideal solution (b) 15.0 g of an unknown molecular material is dissolved in 450g of water . The resulting solution freezes at -0.34^(@)C . What is the molar mass of the material ? (K_(f) for water = 1.86 K kg mol^(-1))

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