The circuit shown in figure contains two diodes each with a forward resistance of `50Ω` and infinite reverse resistance.If the battery voltage is 6 v ,then the current through the `100Ω` resistance is

Explanation

As per given circuit, diode `D_(1)` is forward biased and offers a resistance of 50 ohm. Diode `D_(2)` is reverse biased and as its corresponding resistance circuit is as shown in Fig.As all the three resistances are in series, the current through them is

`I=(6V)/((50+150+100)W)=(6)/(300)A=0.02A`