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Current amplification factor of a common...

Current amplification factor of a common base configuration is 0.88. Find the value of base current when the emitter current is 1 mA.

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In a common-base arrangement, the current amplification factor.
`alpha=((DeltaI_(C))/(DeltaI_(E)))_(V_(CB))=(I_(C))/(I_(B))," Given "alpha=0.88, I_(E)=1mA`
`therefore` Collector current `I_(C)=alphaI_(E)=0.88xx1=0.88mA`.
Now since `I_(E)=I_(B)+I_(C)`
`therefore` Base current `I_(B)=I_(E)-I_(C)=1-0.88=0.12mA`.
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