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A and B do a work in 18 days, B and C do...

A and B do a work in 18 days, B and C do it in 15 days while C and A in 20 days. In how many days A, B and C all working together can finish the same work?

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To solve the problem, we need to find the individual work rates of A, B, and C based on the information provided about their combined work rates. Let's break it down step by step. ### Step 1: Determine the work rates of A+B, B+C, and C+A - A and B can complete the work in 18 days. - B and C can complete the work in 15 days. - C and A can complete the work in 20 days. ### Step 2: Calculate the work done per day by each pair - Work done by A and B in one day = \( \frac{1}{18} \) (since they complete the work in 18 days) - Work done by B and C in one day = \( \frac{1}{15} \) - Work done by C and A in one day = \( \frac{1}{20} \) ### Step 3: Set up equations based on the work rates Let the work done by A in one day be \( a \), by B be \( b \), and by C be \( c \). From the information given, we can write the following equations: 1. \( a + b = \frac{1}{18} \) (Equation 1) 2. \( b + c = \frac{1}{15} \) (Equation 2) 3. \( c + a = \frac{1}{20} \) (Equation 3) ### Step 4: Solve the equations We can add all three equations: \[ (a + b) + (b + c) + (c + a) = \frac{1}{18} + \frac{1}{15} + \frac{1}{20} \] This simplifies to: \[ 2a + 2b + 2c = \frac{1}{18} + \frac{1}{15} + \frac{1}{20} \] Now, we need to find a common denominator for the right side. The least common multiple of 18, 15, and 20 is 180. Converting each fraction: - \( \frac{1}{18} = \frac{10}{180} \) - \( \frac{1}{15} = \frac{12}{180} \) - \( \frac{1}{20} = \frac{9}{180} \) Adding these gives: \[ \frac{10 + 12 + 9}{180} = \frac{31}{180} \] Thus, we have: \[ 2(a + b + c) = \frac{31}{180} \] Dividing both sides by 2: \[ a + b + c = \frac{31}{360} \] ### Step 5: Calculate the time taken by A, B, and C together The combined work rate of A, B, and C is \( \frac{31}{360} \). To find the time taken to complete the work together, we take the reciprocal of their combined work rate: \[ \text{Time} = \frac{1}{\frac{31}{360}} = \frac{360}{31} \] ### Final Answer Thus, A, B, and C together can finish the work in \( \frac{360}{31} \) days, which is approximately 11.61 days. ---
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