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Three persons A, B and C together undert...

Three persons A, B and C together undertake to complete a piece of work for Rs 1600. A can complete the work alone in 6 days, B alone in 15 days and C alone in 24 days respectively. If they complete the work with the help of person D in 3 days, then find the wage of person D?

A

A)Rs 250

B

B)Rs 350

C

C)Rs 210

D

D)Rs 280

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine the individual work rates of A, B, and C, and then find out how much work D contributes when they all work together. Finally, we will calculate D's wage based on the total payment for the work done. ### Step-by-Step Solution: 1. **Calculate the work rate of A, B, and C:** - A can complete the work in 6 days, so A's work rate is: \[ \text{Work rate of A} = \frac{1 \text{ work}}{6 \text{ days}} = \frac{1}{6} \text{ work/day} \] - B can complete the work in 15 days, so B's work rate is: \[ \text{Work rate of B} = \frac{1 \text{ work}}{15 \text{ days}} = \frac{1}{15} \text{ work/day} \] - C can complete the work in 24 days, so C's work rate is: \[ \text{Work rate of C} = \frac{1 \text{ work}}{24 \text{ days}} = \frac{1}{24} \text{ work/day} \] 2. **Find the combined work rate of A, B, and C:** - To find the combined work rate of A, B, and C, we add their individual work rates: \[ \text{Combined work rate of A, B, C} = \frac{1}{6} + \frac{1}{15} + \frac{1}{24} \] - To add these fractions, we need a common denominator. The LCM of 6, 15, and 24 is 120. - Convert each fraction: \[ \frac{1}{6} = \frac{20}{120}, \quad \frac{1}{15} = \frac{8}{120}, \quad \frac{1}{24} = \frac{5}{120} \] - Now, add them: \[ \frac{20}{120} + \frac{8}{120} + \frac{5}{120} = \frac{33}{120} \] 3. **Calculate the total work done by A, B, C, and D in 3 days:** - The total work done by A, B, and C in one day is \(\frac{33}{120}\). Therefore, in 3 days: \[ \text{Work done by A, B, C in 3 days} = 3 \times \frac{33}{120} = \frac{99}{120} = \frac{33}{40} \] - Since they completed the work with the help of D, the total work done in 3 days is 1 (the whole work): \[ \text{Work done by D in 3 days} = 1 - \frac{33}{40} = \frac{7}{40} \] 4. **Calculate the work rate of D:** - The work rate of D can be found by dividing the work done by D in 3 days by 3: \[ \text{Work rate of D} = \frac{7/40}{3} = \frac{7}{120} \text{ work/day} \] 5. **Determine the total efficiency of A, B, C, and D:** - The total efficiency when A, B, C, and D work together is: \[ \text{Total efficiency} = \frac{33}{120} + \frac{7}{120} = \frac{40}{120} = \frac{1}{3} \text{ work/day} \] 6. **Calculate the wage of D:** - The total payment for the work is Rs 1600. Since the total efficiency is 40 units (from the work done in 3 days), we can find the value of 1 unit of work: \[ \text{Value of 1 unit} = \frac{1600}{40} = 40 \text{ Rs} \] - D's share of work is 7 units (from the work done in 3 days), so D's wage is: \[ \text{D's wage} = 7 \times 40 = 280 \text{ Rs} \] ### Final Answer: D's wage is Rs 280.
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ADDA247-TIME AND WORK & PIPE AND CISTERN -PRELIMS QUESTIONS (LEVEL - 2)
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  14. Three persons A, B and C together undertake to complete a piece of wor...

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  15. A does 66(2)/(3)% of work in 8 days and is replaced by B and B complet...

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  17. Three persons A, B and C together undertake to complete a piece of wor...

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