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Train A travelling at 72 kmph crosses an...

Train A travelling at 72 kmph crosses another train of half of its length travelling in opposite direction at speed of 90 kmph in 6 seconds. If train A crosses a platform in 29 seconds, then what is the length of the platform?

A

A)400 meter

B

B)540 meter

C

C)480 meter

D

D)490 meter

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Determine the Length of Train A 1. **Assume the length of Train A**: Let the length of Train A be \( L \). 2. **Length of Train B**: Since Train B is half the length of Train A, its length is \( \frac{L}{2} \). 3. **Relative Speed Calculation**: The relative speed of the two trains when they are moving towards each other is the sum of their speeds: \[ \text{Speed of Train A} = 72 \text{ km/h} = \frac{72 \times 5}{18} = 20 \text{ m/s} \] \[ \text{Speed of Train B} = 90 \text{ km/h} = \frac{90 \times 5}{18} = 25 \text{ m/s} \] \[ \text{Relative Speed} = 20 + 25 = 45 \text{ m/s} \] 4. **Distance Covered in 6 seconds**: The total distance covered when both trains cross each other is: \[ \text{Distance} = \text{Relative Speed} \times \text{Time} = 45 \text{ m/s} \times 6 \text{ s} = 270 \text{ m} \] 5. **Equation for Lengths**: The total distance is equal to the sum of the lengths of both trains: \[ L + \frac{L}{2} = 270 \] \[ \frac{3L}{2} = 270 \] \[ 3L = 540 \implies L = 180 \text{ m} \] Thus, the length of Train A is **180 meters**. ### Step 2: Calculate the Length of the Platform 1. **Total Distance when Train A crosses the platform**: The total distance covered when Train A crosses the platform is the length of Train A plus the length of the platform \( P \): \[ \text{Total Distance} = L + P = 180 + P \] 2. **Speed of Train A in m/s**: We already calculated the speed of Train A as \( 20 \text{ m/s} \). 3. **Distance Covered in 29 seconds**: The distance covered by Train A while crossing the platform is: \[ \text{Distance} = \text{Speed} \times \text{Time} = 20 \text{ m/s} \times 29 \text{ s} = 580 \text{ m} \] 4. **Setting up the equation**: Now we can set up the equation: \[ 180 + P = 580 \] \[ P = 580 - 180 = 400 \text{ m} \] ### Conclusion The length of the platform is **400 meters**. ---
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