A given sample of pure compound contains `9.81 g` of `Zn`, `1.8xx10^(23)` atoms of chromium, and `0.60` mol of oxygen atoms. What is the simplest formula?

A compound contains 26.57% potassium, 35.36% chromium and the remaining oxygen. What is its empirical formula? (At.wt. of K=39.1, Cr=52, 0=16)

1 gram of hydrogen contains 6xx10^(23) atoms. Then 4 grams of He contains

The weight of a gaseous mixture containing 12.044xx10^(23) atoms of He and 3.011xx10^(23) molecules of hydrogen is _____________g.

When we concept that one mole of a substance contains the same numbers of elementary entities or one mole of any other substance, we don’t actually need to know what that number is. Sometimes however we will need to work with the actual number of elementary entities in a mole of substance. This number is called Avogadro.s number. N_(A)=6.022137xx10^(23) molecules The unit mol^(-1) which we read as per mole signifies that a collection of N_(A) molecular level entities is equivalent to one mole at the macroscopic level. For example a mole of carbon contains 6.02xx10^(23) atoms of C. A mole of oxygen gas contains 6.02xx10^(23) molecules of O_(2) . The number of atoms present in 8 g of ozone is

A sample of paramagnetic salt contains 2.0 xx 10^(24) atomic dipoles each of dipoles moment 1.5 xx 10^(-23) J T^(-1) . The sample is placed under a homogeneous magnetic field of 0.64 T, and cooled to a temperature of 4.2K. The degree of magnetic saturation achieved is equal to 15%. What is the total dipole moment of the sample for a magnetic field of 0.98 T and a temperature of 2.8 K? (Assume Curie's law)

A camphor sample melts at 176^(@)C.K_(f) for camphor is 40 K kg mol^(-1) . A solution of 0.02 g of a hydrocarbon in 0.8 g of camphor melts at 156.77^(@)C . The hydrocarbon is made up of 92.3% of carbon. What is the molecular formula of the hydrocarbon?