On analysis, a certain compound was found to contain iodine and oxygen in the ratio of 254:80. The formula of the compound is (At mass I = 127, O = 16)

A compound contains carbon and hydrogen in the mass ratio 3:1. The formula of the compound is

A compound contains carbon and hydrogen in the mass ratio 3:1 . The formula of the compound is

A compound on analysis was found to contain 53.33 % C , 15.5 % H , and the rest nitrogen . The formula of the compound is

A hydrocarbon was found to contain 91.3%C . The molecular formula of the compound is

Vapour density of a compound is 39. It contains carbon and hydrogen atoms in the ratio 1 : 1 . Its molecular formula is

A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16].

An organic compound on analysis was found to contain 0.032% of sulphur. The molecular mass of the compound. If its molecule contains two sulphur atoms, is

An organic compound on analysis was found to contain 16.27% carbon. 0.67% Hydrogen, 72.2% chlorine. The V.D. of the compound is equal to 73.75. Calculate the empirical formula and molecular formula of the compound.

Analysis of an organic compound gave 40%C, 6.6%H by weight and the remaining is oxygen. If the molecular weight of the compound is 90 what is molecular formula?

An organic compound contains carbon, hydrogen, oxygen and nitrogen in the weight ratio 3:1:8:3.5 . Calculate its empirical formula.