A sample of peanut oil weighing 1.5763 g...

A sample of peanut oil weighing `1.5763 g` is added to `25 mL` of `0.4210 M KOH`. After saponification is complete `8.5 mL` of `0.28 M H_(2)SO_(4)` is needed to neutralize excess `KOH`. The saponification number of peanut oil is:

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