In the electrolysis of aqueous `NaCl` ,what volume of `Cl_2`(g) is produced in the time that it takes to liberate 5.0 liter of `H_2`(g) ? Assume that both gases are measured at STP.
A
5
B
2.5
C
7.5
D
10
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
What volume of CO_(2) is obtained at STP by heating 4 g of CaCO_(3) ?
50g of a good sample of CaOCl_2 , is made to react with CO_2 . The volume of Cl_2 liberated at S.T.P is
What is the volume of oxygen liberated at S.T.P When 3.4g of H_(2)O_(2) is heated?
In electrolysis of NaCl when Pt electode is taken then H_2 is liberated at cathode while with Hg cathode, it forms sodium amalgam. This is because
The volume of liberated at STP from 20ml of Vol H_(2)O_(2) is
An acidic solution of Cu^(2+) salt containing 0.4 g of Cu^(2+) is electrolysed until all the copper is deposited. The electrolysis is continued for seven more minutes with the volume of solution kept at 100 ml and the current at 1.2 amp. Calculate the volume of gases evolved at NTP during the entire electrolysis.