Given the listed standard electrode potentials, what is `E^(@)` for the cell: `4BiO^+(aq)+3N_2H_5^+(aq)to4Bi(s)+3N_2(g)+4H_2O(l)+7H^+(aq)` `N_2(g)+5H^+(aq)+4e^(-)toN_2H_5^+(aq),E^(@)=-0.23V` `BiO^+(aq)+2H^+(aq)+3e^(-)toBi(s)+H_2O(l),E^(@)=+0.32V`
A
0.55
B
0.34
C
1.88
D
0.09
Text Solution
Verified by Experts
The correct Answer is:
A
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Given the following standard electrode potentials , PbBr_2(s) + 2e^(-) to Pb(s) + 2Br^(-) (aq) , E^@ - 0.248 V Pb^(2+)(aq) + 2e^(-) to Pb(s) , E^(@) - 0.126 V . If the K_(sp) for PbBr_2 is 7.4 xx 10^(-x) , x is
The standard electrode potential for the following reaction is + 1.33V.What is potential at pH=2.0? Cr_2O_7^(2-) (aq. 1M) + 14H^(+)(aq) + 6e^(-) to 2Cr^(3+) (aq. 1M0 + 7H_2O(l)
The standard reduction potentials at 298 K for the following half cell reactions are given below Zn^(2+) (aq) + 2e^(-) to Zn (s)-0.762 Cr^(3+) (aq) + 3e^(-) to Cr (s)-0.740 2H^(+) (aq) + 2e^(-) to H_(2) (g)-0.000 Fe^(3+) (aq) + e^(-) to Fe^(3+) (aq)-0.770 Which one is the strongest reducing agent?
Calculate Delta G^(@) for the following cell reaction. Zn_((s)) + Ag_(2)O_((s)) + H_(2)O((I)) to Zn_(aq)^(2+) + 2Ag(s) + 2OH_((aq))^(-) E_((Ag^(+))/(Ag))^(@) =+0.80V and E_((Zn^(2+))/(Zn)) ^(@)=-0.76V
Which one of the following statements is correct for the reaction? CH_(3)COOC_(2)H_(5)(aq) + NaOH(aq) to CH_(3)COONa(aq) + C_(2)H_(5)OH(aq)
Define average rate of a reaction. How is the rate of reaction expressed in term of charge in the concentration of reactansts and products for the following reactions. 1) 2HI_((g))to H_(2(g))+I_(2(g)) 2) Hg_((l))+CL_(2(g))to Hg Cl_(2(g)) 3) 5 Br _((aq))+ BrO_((aq))^(-) +6H_((aq))^(+)to 3 Br _(2(aq)) +3H_(2) O_((l))
Balance the following equations in basic medium by ion-electron method and oxidation number methods and identify the oxidising agent and the reducing agent. (a) P_(4)(s) + OH^(-) (aq) rarr PH_(3) (g) + HPO_(2)^(-) (aq) (b) N_(2)H_(4)(I) + ClO_(3)^(-) (aq) rarr NO(g) + Cl^(-) (g) (c) Cl_(2)O_(7) (g) + H_(2)O_(2) (aq) rarr ClO_(2)^(-) (aq) + O_(2)(g) + H^(+)
If the value of equilibrium constant (K_f) for the operation Zn_((aq))^(2+) + 4OH_((aq))^(-) iff Zn(OH)_(4(aq))^(2-) is 10^(10x) , then x is (Given : Zn_((aq))^(2+) + 2e^(-) to Zn_((s)) , E^(@)=-0.76 V , Zn(OH)_(4(aq))^(2-) + 2e^(-) to Zn_((s)) + 4OH_((aq))^(-) , E^(@) = - 1.36 V , 2.303 (RT)/(F) = 0.06 )