If the value of equilibrium constant `(K_f)` for the operation `Zn_((aq))^(2+) + 4OH_((aq))^(-) iff Zn(OH)_(4(aq))^(2-)` is `10^(10x)`, then x is (Given : `Zn_((aq))^(2+) + 2e^(-) to Zn_((s)) , E^(@)=-0.76 V , Zn(OH)_(4(aq))^(2-) + 2e^(-) to Zn_((s)) + 4OH_((aq))^(-) , E^(@) = - 1.36 V , 2.303 (RT)/(F) = 0.06`)
A
`10^10`
B
`2xx10^10`
C
`10^20`
D
None of these
Text Solution
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The correct Answer is:
C
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