A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of `2.768xx10^(-3)ohm^(-1)cm^(-1)` . If its resistance is 82.4 ohm at `25^(@)` C the cell constant is:
A
`0.2182cm^(-1)`
B
`0.2281cm^(-1)`
C
`0.2821cm^(-1)`
D
`0.2381cm^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
B
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Equivalent conductance of saturated BaSO_4 is 400 ohm^(-1) cm^(2) "equiv"^(-1) and specific conductance is 8 xx 10^(-5) ohm^(-1), cm^(-1) . Hence K_(sp) of BaSO_4 is
Specific conductance of 0.1 M sodium chloride solution is 1.06xx10^(-2)ohm^(-1)cm^(-1) . Its molar conductance in ohm^(-1)cm^(2)mol^(-1) is
Specific conductance of 0.1 M Nitric acid is 6.3 xx 10^(-2) "ohm"^(-1) cm^(-1) "mol"^(-1) The molar conductance of the solution is
The specific conductance of 0.1N KCl solution at M 23^@C is 0.012 ohm^(-1)cm^(-1) . The resistance of cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be
The resistance of 0.1N KCl solution is found 702Omega awhen measured in a conductivity cell. The specific conductance of 0.1N KCl is 0.14807 Omega^(-1)m^(-1) . Calculate the cell constant.
In which of the following the conductivity would be in the order of 10^(-4) ohm^(-1)cm^(-1)
The specific conductance of a salt of 0.01M solution is 1.061xx10^(-4)ohm^(-1)cm^(-1) . Molar conductance of a same solution is ( in ohm^(-1)cm^(2)"mole"^(-1) )
The conductivity of 0.1 M KCl solution is 1.29 S m^(-1) . If the resistance of the cell filled with 0.1 M KCl is 100 Omega , Calculate the cell constant.
At 25^@C , the specific conductance of 0.01 M alkaline earth metal chloride is 0.000158 "ohm"^(-1) cm^(-1) Calculate the equivalent conductance.
