Home
Class 11
CHEMISTRY
The cell Pt|H(2)(g,01 bar) |H^(+)(aq),pH...

The cell `Pt|H_(2)(g,01` bar) `|H^(+)(aq),pH=x||Cl^(-)(1M)|Hg_(2)Cl_(2)|Hg|Pt` has emf of 0.5755 V at `25^(@)C` the SOP of calomel electrode is `-0.28V` then pH of the solution will be

A

11

B

4.5

C

5.5

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

The pH of a 0.005 M H_2SO_4 solution is

The EMF of the cell Ni//Ni^(2+)(0.01)// // Cl^(-)(0.01M)//Cl_(2) , pt is -----V if the SRP of nickel and chlorine electrodes are -0.25V and +1.36V respectively

50 ml of 0.2 M HCl is added to 30 ml of 0.1 MKOH solution. Find the pH of the solution.

The e.m.f of the cell : H_2(g) |Buffer | Normal calomel electrodes is 0.6885 volt at 25^(@)C , when barometric pressure is 760 mm Hg. What is the pH of the buffer solution ? Given E_("calomel")^(@) = 0.28 volt

The pH of a 0.05 M solution of H_(2)SO_(4) is

At 25^@C potential of the cell, Pt, H_2(g), HCl (aq)"//"AgCl(s), Ag(s) is 0.22 V. If E^@ of silver electrode is 0.8 V , calculate the solubility of AgCI in water .

The potential of the cell Cu, Cu^(2+) (0.1M)"//"HCl (xM), Cl_(2), Pt is 1.07 V. If the standard potential of copper and chlorine electrodes are 10.34 V and 1.36 V, calculate the concentration of HCI.

The EMI of the cell Pt, H_(2)(2 atm) |HCl (1M)|H_2(10 atm),Pt is xV and of Pt, Cl_(2)(2 atm)|HCl (1M)|Cl_2(10 atm),Pt is yV . How are x and y related?