The cell `Pt|H_2(g,0.1"bar")|H^+(aq),PH=X"||"Cl^-)(aq,1M)|Hg_2Cl_2|Hg|Pt`, has e.m.f of 0.5755V at `25^(@)C`. The SOP of calomel electrode is `-0.28V` , then pH of solution will be:
A
0.051V
B
-0.051
C
0.102V
D
0.0255V
Text Solution
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The correct Answer is:
A
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