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Given the following molar conductivities...

Given the following molar conductivities are ` 25^(@) C `, HCl , `426 Omega^(-1) cm^(2) mol^(-1)`, NaCl , `126 Omega^(-1)cm^(2) mol^(-1)`, NaC( sodium crotonate ) , `83 Omega^(-1) cm^(2) mol^(-1)` , what is the ionization constant of crotonic acid ? If the conductivity of a 0.001 M corotonic acid solution is ` 3.83 xx 10^(-5) Omega^(-1) cm^(-1) ?`

A

`10^(-5)`

B

`1.11xx10^(-5)`

C

`1.11xx10^(-4)`

D

0.01

Text Solution

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The correct Answer is:
B
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