Equivalent conductivity of `BaCl_2,H_2SO_4` and HCl, are `x_1,x_2andx_3` `Scm^(-1)eq^(-1)` at infinite dilution. If conductivity of saturated `BaSo_4` solution is x`Scm^(-1)`, then `K_(sp)` of `BaSO_4` is :
A
`(500x)/((x_1+x_2-2x_3)^2)`
B
`(10^6x^2)/((x_1+x_2-2x_3)^3)`
C
`(2.5xx10^5x^2)/((x_1+x_2-x_3)^2)`
D
`(0.25x^2)/((x_1+x_2-2x_3)^2)`
Text Solution
Verified by Experts
The correct Answer is:
C
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Equivalent conductivity of a weak acid HA at infinite dilution is 390 S cm^(2) eq^(-1) . Conductivity of 1xx10^(-3) N HA solution is 4.9xx10^(-5) S cm^(-1) . Calculate the extent of dissociation and dissociation constant of the acid.
Molar conductances of BaCl_(2), H_(2)SO_(4) and HCl at infinite dilution are and X_(1),X_(2) , and X_(3) respectively. Molar conductance of BaSO_(4) at infinte dilution is
The solubility of PbSO_4 "in" 0.01 M Na_2SO_4 solution is (K_(sp) of PbSO_4 is 1.25 xx 10^(-9) )
Limiting molar conductivity of Mg^(2+) and Cl^(-) ions in water is 106.0 and 76.3 S cm^2 "mol"^(-1) . The limiting molar conductivity of magnesium chloride (in Scm^2 " mol"^(-1) ) in water is
The equivalent conductivity of 0.1 N CH_3COOH at 25^@ C is 80 and at infinite dilute is 400ohm cm^(2) eq^(-1) . The degree of dissociation of CH_3COOH
The molar conductivities of H^(+) and HCOO^(-) ions at infinite dilution are 34.7 and 5.4 mSm^(2) " mol"^(-1) respectively. The molar conductivity of 0.25 M HCOOH is 4.0 mSm^(2) mol^(-1) . Then pK_(a) of formic acid is
Equivalent conductance of saturated BaSO_4 is 400 ohm^(-1) cm^(2) "equiv"^(-1) and specific conductance is 8 xx 10^(-5) ohm^(-1), cm^(-1) . Hence K_(sp) of BaSO_4 is
Limiting equivalent conductivities of different ions are given below The limiting equivalent conductivity of the salt NaKSO_4 is __________ Scm^(2)eq^(-1)
