molar conductivity`(bidwedge_m)` is defined as conducting power of the ions producedd by 1 mole of an electrolyte in a solution. `bidwedge_m=K/C` Where k is conductivity `(Scm^2mol^(-1))` and C is molar concentration `(in mol//cm^3)` The molar conductivity of 0.04 M solution of `MgCl_2` is 200 `Scm^3mol^(-1)` at 298 k. A cell with electrodes that are 2.0`cm^2` in surface area and 0.50cm apart is filled with `MgCl_2` solution How much current will flow when the potential difference between the two electrodes is 5.0V?
A
156.25V
B
0.16A
C
160A
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
B
Topper's Solved these Questions
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ELECTROCHEMISTRY
NARENDRA AWASTHI|Exercise Level 1 (Q.91 To Q.120)|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Molar conductivity (^^_m) is defined as conducting power of the ions produced by 1 mole of an electrolyte in a solution. ^^_m =(K)/(C) where K is conductivity (in S-cm^(-1) ), ^^_m is molar conductivity (in Scm^(2) mol^(-1) ) and C is molar concontration (in "mole"//cm^(3) ) The molar conductivity of 0.04 M solution of MgCl_2 is 200Scm^2 mol^(-1) at 298 K. A cell with electrodes that are 2.0cm^(2) in surface area and 0.50 cm apart is filled with MgCl_2 solution. The cell constant is
The conductivity of 0.20M solution of KCl at 298 K is 0.0248S cm^(-1). Calculate molar conductance.
For an electrolytic solution of 0.05 mole "litre"^(-1) , the conductivity has been found to be 0.0110 S cm^(-1) . The molar conductivity (in Scm^(2) "mole"^(-1) ) is
Define molar conducticity ^^_(m) and how is it related to conductivity (K) ?
Molar ionic conductivities of a bivalent electrolyte are 57 and 73. The molar conductivity of the solution will be