The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. K_(b) for benzene is 2.53" K kg mol"^(-1) .
The mole fraction of solute in 20% aqueous H_(2)O_(2) solution is
2g of a non-electrolyte solute dissolved in 200 g of water shows an elevation of boiling point of 0.026^(@)C. K_(b) of water is 0.52 K . "mole"^(1) kg then the molecular weight of solute is x xx100 . What is the value of 'x'?
The number of atoms of hydrogen present in 1.5 mole of H_(2)O is
1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The Boiling point of the solution is (K_(b) of H_(2)O=0.52K kg mol^(-1))
Number of moles of O_2 gas evolved by the decomposition of 1 lit of 1N H_2O_2 solution is
A solution of sucrose (molar mass 342 "gmol"^(-1) ) has been produced by dissolving 68.5g sucrose in 1000g water. The freezing point of the solution obtained will be ( K_f for H_2O = 1.86 kg "mol"^(-1) )
An aqueous solution of H_(2)O_(2) is purified by
31 g of ethylene glycol (C_2H_6O_2) is dissolved in 600g of water. The freezing point depression of the solution is (K_f for water is 1.86 K Kg mol^-1)
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
