The boiling point elevation for toluene is `3.32` K `kg "mol"^(-1)` . The normal boiling point of toluence is `110.7^(@)C` . The enthalpy of vapourization of the toluene would be nearly :
A
`17.0 kjmol^(-1)`
B
`34.0 kjmol^(-1)`
C
`51.0 kjmol^(-1)`
D
`68.0 kjmol^(-1)`
Text Solution
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The correct Answer is:
b
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