A solution of sucrose (molar mass 342 "gmol"^(-1) ) has been produced by dissolving 68.5g sucrose in 1000g water. The freezing point of the solution obtained will be ( K_f for H_2O = 1.86 kg "mol"^(-1) )
Equal volumes of 1.0M AgNO_(3) and 1.0M KCl are mixed . The depression of freezing point of the resulting solution will be (K_(f)(H_(2)O)=1.86 K kg "mol"^(-1), 1M=1m)
1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The Boiling point of the solution is (K_(b) of H_(2)O=0.52K kg mol^(-1))
A 0.5 molal aqueous solution of a weak acid (HX) is 20 percent ionized. The lowering in freezing point of this solution is ( K_f = 1.86 K/m for water)
31 g of ethylene glycol (C_2H_6O_2) is dissolved in 600g of water. The freezing point depression of the solution is (K_f for water is 1.86 K Kg mol^-1)
A decimolar solution of K_4[Fe(CN)_6] at 300K is 50% dissociated, then, osmotic pressure of the solution is
If aqueous solution contains 9% and 1% (W//W) of two non- volatile non- electrolytes X (molecular weight 180) and Y (mulecular weight 50 ) respectively the boiling point of solution in .^(@)C approximately is (k_(b) = 0.52 kg mol^(-1))
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
