Equal volumes of 1.0M AgNO_(3) and 1.0M KCl are mixed . The depression of freezing point of the resulting solution will be (K_(f)(H_(2)O)=1.86 K kg "mol"^(-1), 1M=1m)
Calculate the depression in the freezing point of a solution containing 0.1 g of K_(3)[Fe(CN)_(6)] in 100 g of H_(2)O ? (molecular weigth of K_(3)[Fe(CN)_(6)]=329, K_(f)=1.86K " kg mol"^(-1) )
0.1M KI and 0.2 M AgNO_(3) are mixed in 3:1 volume ratio . The deperession in freezing point of the resulting solution will be 0.1 x (Assume Kf of H_(2)O=2Kg//"mol" ).
A solution of sucrose (molar mass 342 "gmol"^(-1) ) has been produced by dissolving 68.5g sucrose in 1000g water. The freezing point of the solution obtained will be ( K_f for H_2O = 1.86 kg "mol"^(-1) )
2 g of benzoic acid (C_(6)H_(5)COOH) dissolved in 25g of benzene shows a depression in freezing point equal to 1.62 K. Molal depression constant for benzene is 4.9 K kg "mol"^(-1) . What is the precentage association of acid if it forms dimer in solution ?
12.25 g of CH_(3)CH_(2)CHCICOOH is added to 250 g of water to make a solution . If the dissociation constant of above acid is 1.44xx10^(-3) the depression in freezing point of water in ""^(@)C "is" (K_(f) for water is 1.86 K kg "mol"^(-1))
A solution containing 25. 6 gm of sulphur dissolved in 1000 gm of napthalene gave a freezing point lowering of 0.680, then molecular formula of sulphare is (K_(f) for naphthalene=6.8K kg mol^(-1) )
Mole fraction of solute in some solution is 1//n . If 50% of solute molecules dissociate into two parts and remaining 50% get dimerised , new mole fraction of solvent becomes 4//5 . Find value of n.29. 0.1 M KI and 0.2 M are mixed in 3:1 volume ratio . The depression in freezing point of the resulting solution will be 0.1 x (Assume K_(f) of and molality =molarity). Then x=_________
1.0 molal aqueous solution of an electrolyte X_(3)Y_(2) is 25% ionized. The Boiling point of the solution is (K_(b) of H_(2)O=0.52K kg mol^(-1))
NARENDRA AWASTHI-DILUTE SOLUTION-Level 3 - Match The Column
