Home
Class 11
CHEMISTRY
The intercept on y-axis and slope of cur...

The intercept on y-axis and slope of curve plotted between P/T vs. T
( For an ideal gas having 10 moles in a closed rigid container of volume 8.21 L. (P= Pressure in atm and T = Temp. in K, `log_(10)2=0.30))` are respectively :

A

0.01, 0

B

0.1, 0

C

0.1, 1

D

10, 1

Text Solution

Verified by Experts

The correct Answer is:
b

(b) Intercept on y-axis
`=log_(10)""(nR)/(V)=log_(10)""(10xx0.0821)/(8.21)=-1.0`
`(P)/(T) v//s " curve" (P)/(T)=(nR)/(V)`
`"intercept"=(nR)/(V)`
`=(10xx0.0821)/(8.21)=0.1," slope"=0`
Promotional Banner

Topper's Solved these Questions

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|1 Videos
  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 1 (Q.121 To Q.150)|1 Videos
  • ELECTROCHEMISTRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos
  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Assertin-Reason Type Questions|1 Videos

Similar Questions

Explore conceptually related problems

The intercepts and slope of graph of log K_(p)^(@) "Vs" (1)/(T) are :

A graph is ploted between log V and log T for two moles of gas at constant pressure of 0.0821 atm. [V and T are in litres and kelvin]. Then which of the following is/are correct

n moles of an ideal gas at temperature, T (in kelvin) occupy VL of volume, exerting a pressure of P atmospheres. What is the concentration (in mole //L ) ?

Draw the P-T and V-T diagrams for an isothermal process, corresponding to one mole of an ideal gas at an initial pressure and volume P_(0) and V_(0) respectively, expanding to a volume 2V_(0) .

A quantity of 4.0 moles of an ideal gas at 20^(@)C expands isothermally against a constant pressure of 2.0 atm from 1.0 L to 10.0L. What is the entropy change of the system (in cals)?